Class 8 Mathematics Notes Chapter 9 (Algebraic Expressions and Identities) – Mathematics Book
Alright class, let's focus on Chapter 9: Algebraic Expressions and Identities. This is a foundational chapter, and understanding it well is crucial not just for your Class 8 exams but also for various government exams where quantitative aptitude is tested. Pay close attention!
Chapter 9: Algebraic Expressions and Identities - Detailed Notes
1. What are Expressions?
- An expression is a combination of constants, variables, and mathematical operators (+, -, ×, ÷).
- Example:
5x
,2x - 3
,4xy + 7
,x² + 1
2. Terms, Factors, and Coefficients
- Terms: Parts of an expression separated by '+' or '-' signs.
- In
4xy + 7
, the terms are4xy
and7
.
- In
- Factors: When a term is formed as a product of numbers and/or variables, these numbers/variables are its factors.
- In the term
4xy
, the factors are4
,x
, andy
. - The term
7
has only one factor,7
.
- In the term
- Coefficient: The numerical factor of a term is called its coefficient.
- In
4xy
, the coefficient is4
. - In
-5x²y
, the coefficient is-5
. - If a term is just a variable like
y
, the coefficient is1
. If it's-y
, the coefficient is-1
.
- In
3. Monomials, Binomials, Trinomials, and Polynomials
- Monomial: An algebraic expression containing only one term.
- Examples:
7xy
,-5m
,3z²
,4
- Examples:
- Binomial: An algebraic expression containing two unlike terms.
- Examples:
x + y
,m - 5
,a² + b²
,2x + 3y
- Examples:
- Trinomial: An algebraic expression containing three unlike terms.
- Examples:
x + y + 7
,ab + a + b
,2x² - 3x + 5
- Examples:
- Polynomial: An algebraic expression containing one or more terms with non-negative integer exponents for the variables. Monomials, binomials, and trinomials are all types of polynomials.
- An expression like
x + 1/x
or√y + 3
is not a polynomial because the powers of variables are not non-negative integers (1/x = x⁻¹
,√y = y¹/²
).
- An expression like
4. Like and Unlike Terms
- Like Terms: Terms that have the same algebraic factors (same variables raised to the same power). The coefficients can be different.
- Examples:
7x
and-13x
;5x²y
and9x²y
;-3pq
andpq
- Examples:
- Unlike Terms: Terms that have different algebraic factors.
- Examples:
7x
and7y
;5x²y
and9xy²
;-3pq
and-3p
- Examples:
- Importance: Addition and subtraction operations can only be performed between like terms.
5. Addition and Subtraction of Algebraic Expressions
- Rule: Combine only the like terms. Add or subtract their coefficients, keeping the algebraic factors the same. Unlike terms remain as they are.
- Method 1: Horizontal Method
- Write expressions in a row. Rearrange terms to group like terms together. Combine like terms.
- Example (Addition): Add
(7xy + 5yz - 3zx)
and(4yz + 9zx - 4y)
= 7xy + 5yz - 3zx + 4yz + 9zx - 4y
= 7xy + (5yz + 4yz) + (-3zx + 9zx) - 4y
= 7xy + 9yz + 6zx - 4y
- Example (Subtraction): Subtract
(5x² - 4y² + 6y - 3)
from(7x² - 4xy + 8y² + 5x - 3y)
= (7x² - 4xy + 8y² + 5x - 3y) - (5x² - 4y² + 6y - 3)
= 7x² - 4xy + 8y² + 5x - 3y - 5x² + 4y² - 6y + 3
(Change signs of the subtracted expression)
= (7x² - 5x²) - 4xy + (8y² + 4y²) + 5x + (-3y - 6y) + 3
= 2x² - 4xy + 12y² + 5x - 9y + 3
- Method 2: Column Method
- Write expressions one below the other such that like terms are in the same column. Add or subtract column-wise. Remember to change signs of the lower expression during subtraction.
6. Multiplication of Algebraic Expressions
-
Rule 1 (Signs): (+) × (+) = (+); (-) × (-) = (+); (+) × (-) = (-); (-) × (+) = (-)
-
Rule 2 (Exponents): When multiplying terms with the same base variable, add their exponents (Law of Exponents:
aᵐ × aⁿ = aᵐ⁺ⁿ
). -
a) Multiplying a Monomial by a Monomial:
- Multiply the coefficients.
- Multiply the variable parts (using the law of exponents).
- Example:
(3x) × (5xy) = (3 × 5) × (x × x × y) = 15x¹⁺¹y = 15x²y
- Example:
(-4ab) × (-2a²bc) = (-4 × -2) × (a × a²) × (b × b) × c = 8a¹⁺²b¹⁺¹c = 8a³b²c
-
b) Multiplying a Monomial by a Polynomial:
- Use the Distributive Property: Multiply the monomial by each term of the polynomial.
- Example:
3p × (4p² + 5p + 7) = (3p × 4p²) + (3p × 5p) + (3p × 7)
= 12p¹⁺² + 15p¹⁺¹ + 21p
= 12p³ + 15p² + 21p
-
c) Multiplying a Polynomial by a Polynomial:
- Multiply each term of the first polynomial by each term of the second polynomial. Group like terms and combine them.
- Example:
(x + 7) × (x + 2)
= x × (x + 2) + 7 × (x + 2)
(Distributive property)
= (x × x) + (x × 2) + (7 × x) + (7 × 2)
(Distributive property again)
= x² + 2x + 7x + 14
= x² + 9x + 14
(Combine like terms) - Example:
(a - b) × (2a + 3b - c)
= a × (2a + 3b - c) - b × (2a + 3b - c)
= (a × 2a) + (a × 3b) + (a × -c) + (-b × 2a) + (-b × 3b) + (-b × -c)
= 2a² + 3ab - ac - 2ab - 3b² + bc
= 2a² + (3ab - 2ab) - ac - 3b² + bc
= 2a² + ab - ac - 3b² + bc
7. What is an Identity?
- An identity is an equality that holds true for all possible values of the variables involved.
- Example:
(a + 1)(a + 2) = a² + 3a + 2
. If you puta = 1
, LHS = (2)(3) = 6, RHS = 1+3+2 = 6. If you puta = -1
, LHS = (0)(1) = 0, RHS = 1-3+2 = 0. It's true for any value of 'a'. - This is different from an equation, which is true only for specific values of the variable(s). Example:
x + 5 = 8
is true only forx = 3
.
8. Standard Identities
These are very important and frequently used for simplification and factorization. Memorize them!
-
Identity I:
(a + b)² = a² + 2ab + b²
- Example:
(2x + 3y)² = (2x)² + 2(2x)(3y) + (3y)² = 4x² + 12xy + 9y²
- Example (Calculation):
103² = (100 + 3)² = 100² + 2(100)(3) + 3² = 10000 + 600 + 9 = 10609
- Example:
-
Identity II:
(a - b)² = a² - 2ab + b²
- Example:
(4p - 3q)² = (4p)² - 2(4p)(3q) + (3q)² = 16p² - 24pq + 9q²
- Example (Calculation):
98² = (100 - 2)² = 100² - 2(100)(2) + 2² = 10000 - 400 + 4 = 9604
- Example:
-
Identity III:
(a + b)(a - b) = a² - b²
- Example:
(5m + 3n)(5m - 3n) = (5m)² - (3n)² = 25m² - 9n²
- Example (Calculation):
51 × 49 = (50 + 1)(50 - 1) = 50² - 1² = 2500 - 1 = 2499
- Example:
-
Identity IV:
(x + a)(x + b) = x² + (a + b)x + ab
- Example:
(y + 3)(y + 5) = y² + (3 + 5)y + (3 × 5) = y² + 8y + 15
- Example:
(2t + 5)(2t - 3) = (2t)² + (5 + (-3))(2t) + (5 × -3) = 4t² + (2)(2t) - 15 = 4t² + 4t - 15
(Here x = 2t, a = 5, b = -3) - Example (Calculation):
103 × 104 = (100 + 3)(100 + 4) = 100² + (3 + 4)100 + (3 × 4) = 10000 + 700 + 12 = 10712
- Example:
Key Takeaways for Exams:
- Be very clear about the difference between terms, factors, and coefficients.
- Master identifying like and unlike terms for addition/subtraction.
- Practice multiplication carefully, especially polynomial by polynomial, paying attention to signs and exponents.
- Memorize the four standard identities and practice applying them for both expanding expressions and simplifying numerical calculations quickly.
Multiple Choice Questions (MCQs)
Here are 10 MCQs based on this chapter for your practice:
-
The coefficient of
y²
in the expression-5x²y² + 7xy - 3
is:
A) -5
B) -5x²
C) 5x²
D) 7x -
Which of the following is a binomial?
A) 7xy + 5x - 3y
B) 4a²b
C) p² - q²
D) 100 -
The sum of
(ab - bc)
and(bc - ca)
is:
A) ab - ca
B) ab + ca
C) 2bc
D) ab - 2bc - ca -
On subtracting
(5a² - 3b² + 2ab)
from(a² + b² - ab)
, we get:
A) -4a² + 4b² - 3ab
B) 4a² - 4b² + 3ab
C) 6a² - 2b² + ab
D) -4a² - 4b² - 3ab -
The product of
(-6p²q)
and(3pq²r)
is:
A) 18p³q³r
B) -18p²q²r
C) -18p³q³r
D) -3p³q³r -
The result of
2x (3x + 5y)
is:
A) 6x² + 5y
B) 6x + 10xy
C) 6x² + 10xy
D) 5x² + 7xy -
The product
(x + 5)(x - 3)
is equal to:
A) x² + 8x - 15
B) x² - 2x - 15
C) x² + 2x + 15
D) x² + 2x - 15 -
Using a suitable identity, the value of
(102)²
is:
A) 10404
B) 10004
C) 10400
D) 10204 -
Using the identity
(a - b)² = a² - 2ab + b²
, the value of(9.9)²
is:
A) 98.01
B) 99.81
C) 98.1
D) 9.801 -
The expression
(3x + 7)² - 84x
simplifies to:
A) (3x - 7)²
B) (9x + 49)²
C) (3x + 7)²
D) (9x - 49)²
Answer Key:
- B
- C
- A
- A (Remember to change signs when subtracting)
- C
- C
- D (Using (x+a)(x+b) = x² + (a+b)x + ab, where a=5, b=-3)
- A (Using (100+2)² = 100² + 21002 + 2²)
- A (Using (10 - 0.1)² = 10² - 2100.1 + (0.1)²)
- A (Expand (3x+7)² = 9x² + 42x + 49. Then 9x² + 42x + 49 - 84x = 9x² - 42x + 49, which is (3x-7)²)
Study these notes thoroughly and practice more problems. Good luck with your preparation!